(3-x)(4x-2)=-4x^2-(10x-(15x+12))

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Solution for (3-x)(4x-2)=-4x^2-(10x-(15x+12)) equation: 



(3-x)(4x-2)=-4x^2-(10x-(15x+12))

We move all terms to the left:

(3-x)(4x-2)-(-4x^2-(10x-(15x+12)))=0

We add all the numbers together, and all the variables

-(-4x^2-(10x-(15x+12)))+(-1x+3)(4x-2)=0

We multiply parentheses ..

-(-4x^2-(10x-(15x+12)))+(-4x^2+2x+12x-6)=0



We calculate terms in parentheses: -(-4x^2-(10x-(15x+12))), so:

-4x^2-(10x-(15x+12))



We calculate terms in parentheses: -(10x-(15x+12)), so:

10x-(15x+12)

We get rid of parentheses

10x-15x-12

We add all the numbers together, and all the variables

-5x-12

Back to the equation:

-(-5x-12)



We get rid of parentheses

-4x^2+5x+12

Back to the equation:

-(-4x^2+5x+12)



We get rid of parentheses

4x^2-4x^2-5x+2x+12x-12-6=0

We add all the numbers together, and all the variables

9x-18=0

We move all terms containing x to the left, all other terms to the right

9x=18

x=18/9

x=2

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